Default
Question
Find the vector equation of the line passing through the point 2i+3j+k and parallel to the vector 4i−2j+3k.
Solution
The correct answer is (2+4λ)ˆi+(3−2λ)ˆj+(1+3λ)ˆk
Explanation
Given that the line passes through the point →a = 2i+3j+k
It is parallel to line →b = 4i−2j+3k
The vector equation of the line passing through a point and parallel to the given line as
→r = →a + λ→b
= 2i+3j+k + λ(4i−2j+3k)
= (2+4λ)i+(3−2λ)j+(1+3λ)k
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