Find the shortest distance between the lines

$\overrightarrow{r}$ = $\hat{i} + 2\hat{j} + \hat{k} + \lambda(\hat{i} - \hat{j} + \hat{k})$

$\overrightarrow{r}$ = $2\hat{i} - \hat{j} - \hat{k} + \mu(2\hat{i} + \hat{j} + 2\hat{k})$

The correct answer is $\dfrac{3}{\sqrt{2}}$

Here,

$\overrightarrow{a_{1}}$ = $\hat{i} + 2\hat{j} + \hat{k}$, $\overrightarrow{b_{1}}$ = $\hat{i} - \hat{j} + \hat{k}$

$\overrightarrow{a_{2}}$ = $2\hat{i} - \hat{j} - \hat{k}$, $\overrightarrow{b_{2}}$ = $2\hat{i} + \hat{j} + 2\hat{k}$


∴ $\overrightarrow{a_{2}}$ - $\overrightarrow{a_{1}}$ = $\hat{i} - 3\hat{j} - 2\hat{k}$



$\overrightarrow{b_{1}}$ x $\overrightarrow{b_{2}}$ =
$\left| \begin{matrix} \hat{i} & \phantom{-}\hat{j} & \phantom{-}\hat{k} \\ 1 & \phantom{-}-1 & \phantom{-}1 \\ 2 & \phantom{-}1 & \phantom{-}2 \\ \end{matrix} \right|$ = $-3\hat{i} + 3\hat{k}$


∴ $|\overrightarrow{b_{1}}$ x $\overrightarrow{b_{2}} |$ = $\sqrt{9 + 9}$ = $3\sqrt{2}$


∴ The shortest distance between the given lines is



$d$ = $| \dfrac{(\overrightarrow{b_{1}} \text{x} \overrightarrow{b_{2}}). (\overrightarrow{a_{2}} - \overrightarrow{a_{1}})}{|\overrightarrow{b_{1}} \text{x} \overrightarrow{b_{2}}|}|$

= $\dfrac{| -3 - 6|}{3\sqrt{2}}$

= $\dfrac{3}{\sqrt{2}}$